二‧情報虛實位能差(泡沫)236Please respect copyright.PENANAL63dTZKC1w
236Please respect copyright.PENANAOrKWxjDlPb
錯誤情報與真實情報,會在觀測者與被觀測物之間產生能量差,系統中的量子會從高處往低處流動,捕捉其運動軌跡就能推導未知事件。236Please respect copyright.PENANAgmJucGww9b
236Please respect copyright.PENANApzQ3HwwfXM
例:236Please respect copyright.PENANAZF2xlwIfCV
封閉的箱子中有一顆蘋果,設總熵為1。236Please respect copyright.PENANAKSiQ2Kdsk9
觀測者被告知情報:箱子中有一顆蘋果,總熵為1。236Please respect copyright.PENANAKUkZcpqVw0
開啟箱子,兩系統的總熵相等,因果收束前後沒有情報能量流動。236Please respect copyright.PENANAYurS0CpMOm
236Please respect copyright.PENANADLIaq1K8hn
封閉的箱子中有一顆蘋果,設總熵為1。236Please respect copyright.PENANASUjgM9N4Ou
觀測者被告知情報:箱子中有兩顆蘋果,總熵為2。236Please respect copyright.PENANAFJ83ALw1lp
開啟箱子,兩系統的總熵差1,因果收束前後有情報能量流動。236Please respect copyright.PENANALsBFHESVKu
236Please respect copyright.PENANAf3LmIFN6IE
封閉的箱子中有一顆蘋果,設總熵為1。236Please respect copyright.PENANAmio8zDtXHu
觀測者被告知情報:箱子中有兩顆蘋果,總熵為2。236Please respect copyright.PENANADZIMFXyI0L
不開啟箱子,兩系統的總熵差1,此差異持續存在的狀態,專案內稱之為泡沫。236Please respect copyright.PENANAen94JQnUzR
236Please respect copyright.PENANAjAQ7KTvt0R
封閉的箱子中有一顆蘋果,設總熵為1。236Please respect copyright.PENANARNPbPada13
100名觀測者被告知情報:箱子中有兩顆蘋果,總熵為2*100=200。236Please respect copyright.PENANADu5NZ6B14h
不開啟箱子,兩系統的總熵差199,此差異持續存在的狀態,總共有199顆泡沫。236Please respect copyright.PENANAOrwtOdPpWO
236Please respect copyright.PENANAvWBBEIOpeJ
根據第二定律,宇宙中的情報總熵必定趨向均衡。泡沫產生的混亂必定會分散至其他系統中。比如:多出來的那些「不存在的蘋果」導致價格下跌,果農賺得的能量因而減少。236Please respect copyright.PENANAqp323Crecp
236Please respect copyright.PENANAMBw6DRuK1u
定位、統計、歸納,得知所有粒子的運動狀態就能計算出未來的動向。觀察、分析、統整這些資訊,並導入演算機中的工作,本應交由AI電子腦擔任,但原初智叛亂後,現今局勢反對高性能AI生產,最合乎成本效益的解決方案就是人類頭腦。處理如此複雜的系統需要大量樣本,且必定會出現損壞,最好的方式就是使用Q型複製人。236Please respect copyright.PENANAgs2j1kEQNr
236Please respect copyright.PENANAnxScuO0OcE
(New)236Please respect copyright.PENANAgAKUPg7YRb
新展望:加入纏結粒子技術的精準推導法,下述。236Please respect copyright.PENANAuF5Wgp8DmO
236Please respect copyright.PENANABIKT8Sfhql
arrow_back
拉普拉斯演算機:情報泡沫儲存槽
more_vert
-
info_outline Info
-
toc Table of Contents
-
share Share
-
format_color_text Display Settings
-
exposure_plus_1 Recommend
-
report_problem Report
-
account_circle Login
Search stories, writers or societies
Continue ReadingClear All
What Others Are ReadingRefresh
X
Never miss what's happening on Penana!
拉普拉斯演算機:情報泡沫儲存槽
Author:
LiCh 阿立

ISSUE #2
預知未來的方法:因果率演算理論模型(二)
LIKES 0
READS 232
BOOKMARKS 3
Suggest Edits

Click to load the next chapter
x
will be deducted


Your current coin balance: 0Click to buy coins
A recurring charge will be deducted , unless you decide to cancel. You can cancel your subscription at any time.
You can also pay with credit card
X
After each update request, the author will receive a notification!
smartphone100 → Request update
X
Sponsor again
Click to login
Login first to show your name as a sponsor.
Thank you for supporting the story! :)
Please Login first.
×
Write down what you like about the story
×
Reading Theme:
Font Size:
Line Spacing:
Paragraph Spacing:
Load the next issue automatically
Reset to default
×
People Who Like This